12p^2+8p-26=-2

Solution for 12p^2+8p-26=-2 equation:

12p^2+8p-26=-2

We move all terms to the left:

12p^2+8p-26-(-2)=0

We add all the numbers together, and all the variables

12p^2+8p-24=0

a = 12; b = 8; c = -24;
Δ = b2-4ac
Δ = 82-4·12·(-24)
Δ = 1216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1216}=\sqrt{64*19}=\sqrt{64}*\sqrt{19}=8\sqrt{19}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{19}}{2*12}=\frac{-8-8\sqrt{19}}{24}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{19}}{2*12}=\frac{-8+8\sqrt{19}}{24}
$